Math, asked by thakurajayzb3706, 11 months ago

Tan^2 theata -sec^2 theata

Answers

Answered by Anonymous
4

Answer:

LHS:=tan^2theata+cos^2theata+2

  • sec^2theata-1+cosec^2-1+2
  • sec^2theata+cosec^2theata
  • 1/cos^2theata+1/sin^2theata
  • sin^2theata+cos^2theata/sin^2..cos^2theata
  • 1/sin^2theata..cos^2theata
  • 1/sin^2theata 1/cos^2theata
  • =cos^2theata..sec^2theata

hope this will help u!

~Raniya@~

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