tan^2 theeta (1+cos^2 theeta) find the value
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Answer:
= tan²θ (1 + cos²θ)
= tan²θ ( 1 + (1/sec²θ))
= (sin²θ/cos²θ) [(sec² + 1)/sec²θ]
= (sin²θ sec²θ) (tan²θ/sec²θ)
= sin²θ tan²θ
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