Question

tan^2 x + 1 - root 3 tan x + 1 = 0

Answer 1

Answer:

$x=-1 \\and \\x=59$

Explanation:

Here, the given equation is

$tan^{2}(x+1) - \sqrt{3}  tan (x+1)$

Now, solving the equation

first, we take common tan (x+1)

$=tan (x+1)[tan (x+1)-\sqrt{3}]=0$

So, the solution is

$tan (x+1) - \sqrt{3} =0\\ and\\tan (x+1) =0$

from first term

$tan (x+1) - \sqrt{3} =0$

$tan (x+1) = \sqrt{3}\\ tan (x+1) = tan 60\\x+1 = 60\\x=60-1\\x=59$

from second term,

$tan(x+1)=0\\tan(x+1)= tan0\\x+1= 0\\x=-1$