Math, asked by dilbagranga789pc9jg1, 1 year ago

tan^2 x- sin^2 x= tan^2 x sin^2 x

Answers

Answered by bharatdeepracepax6f3
1
tan²x - sin²x
= sin²x/cos²x ⁻ sin²x
= sin²x (1/cos²x - 1)
= sin²x {1 - cos²x}/{cos²x}
= sin²x . (sin²x/cos²x)
= sin²x . tan²x
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