Math, asked by gopikashyap95p69h5b, 1 year ago

tan 2A = cos (A-18) where a is a acute angle

Answers

Answered by Sanskaar04

Tan 2A=cot(A-18)
Cot(90-2A) =Cot(A-18)
90-2A=A-18
90+18=A+2A
108 = 3A
108/3 = A
36 = A

gopikashyap95p69h5b: it is cos A not cot A

Answered by DivyamRajvanshi

$tan \: 2a = \ \cot (a - 18 ) \\ \cot(90 - 2a ) = \cot(a - 18) \\ 90 - 2a = a - 18 \\ 90 + 18 = 2a + a \\ 108 = 3a \\ a = 36$
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gopikashyap95p69h5b: it is cos a not cot a

gopikashyap95p69h5b: pleas try to solve it to

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