Tan^2A/(Sec^A-1)^2=1+secA
Prove it
Sujeet921:
i will give the answer this evening
Answers
Answered by
1
Hi ,
It may be like this ,
LHS = tan² A / ( secA - 1 )
= ( Sec² A - 1 ) / ( sec A - 1 )
= ( SecA + 1 )( secA - 1 ) / ( secA - 1 )
= ( SecA + 1 )
= RHS
I hope this helps you.
: )
It may be like this ,
LHS = tan² A / ( secA - 1 )
= ( Sec² A - 1 ) / ( sec A - 1 )
= ( SecA + 1 )( secA - 1 ) / ( secA - 1 )
= ( SecA + 1 )
= RHS
I hope this helps you.
: )
Answered by
0
I hope it will help you:)
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