Question

tan{(2n+1) π+theta}+tan{(2n+1) π-theta}=0

Answer 1

Step-by-step explanation:

example

n=1

tan{(2×1+1)π+ a}=+ve Tana

tan{(2×1+1)π - a}=-ve Tana

n=2

tan{(2×2+1)π+a}=+ve Tana

tan{(2×2+1)π -a}=-ve Tana

n=3

tan{(2×3+1)π+a}=+ve Tana

tan{(2×3+1)π -a}= -veTana

n= 1 2 3 4 5........

Similary

LHS

tan{(2n+1)π+a} +tan{(2n+1)-a}

=tana+(-tana)

=tana-tana

=0

RHS proved

I hope you understand