tan^2x/tan^2x-1 + cosec^2x/sec^2-cosec^2 = 1/sin^2x-cos^x
Answers
Answered by
4
We need to prove that:
sec^2 x +csec^2 x = (sec^2 x)(csec^2 x)
Let us start with the left side:
We know that secx= 1/cosx and csec x = 1/sinx
==> sec^2 x+ cosec^2 x= 1/cos^2 x + 1/sin^2 x
= (sen^2 x + cos^2 x)/(sin^2 x)(cos^2 x)
Now we know that sin^2 x + cos^2 x= 1
==> 1/(sin^2 x)(cos^2 x)= (1/sin^2 x)(1/cos^2 x)
= (sec^2 x)*(csec^2 x)
Similar questions
Social Sciences,
7 months ago
English,
7 months ago
English,
1 year ago
Biology,
1 year ago
Math,
1 year ago