Tan^3-1/tan-1=sec^2+tan
Answers
Answered by
3
we can write
(Tan^3-1)=(Tan-1)(Tan^2+Tan+1)---------------------------------------(1)
so putting Tan^3-1 in original equation
we get (Tan^2+Tan+1)------------------------------------------------------(3)
and as we know 1+tan^2=sec^2 (Trignometric identity)--------(2)
put (2) in (3)
so we get sec^2+tan
hence proved
thanks
(Tan^3-1)=(Tan-1)(Tan^2+Tan+1)---------------------------------------(1)
so putting Tan^3-1 in original equation
we get (Tan^2+Tan+1)------------------------------------------------------(3)
and as we know 1+tan^2=sec^2 (Trignometric identity)--------(2)
put (2) in (3)
so we get sec^2+tan
hence proved
thanks
Similar questions