Question

tan 3 A=3tanA-tan³A/1-3tan²A​

Answer 1

Answer:

273738363783

Step-by-step explanation:

25366474364373737

Answer 2

Answer:

Favourite answer

tan 3A

= tan (A + 2A)

= (tan A + tan 2A) / (1 - tan A tan 2A)

= [ tan A + 2 tanA / (1 - tan²A) ] / [ 1 - 2tan²A / (1 - tan²A) ]

= [ (tanA - tan³A + 2tan A) ] / [ 1 - tan²A - 2tan²A ]

= (3tanA - tan³A) / (1 - 3tan²A)...Show more

00

mathmaniac

12 years ago

tan(3A)

= tan(A + 2A)

= (tanA + tan2A)/(1 - tanA tan2A)

For simplicity, let's write tan A as t

So tan2A = 2t/(1-t^2)

Therefore

= (t + 2t/(1-t^2))/(1 - 2(t^2)/(1-t^2))

= (3t - t^3)/(1-3t^2)...Show more

00

Anonymous

12 years ago

The answer is 1 =]...Show more

04

sαṉḋÿ™

12 years ago

Tan3A=Tan(2A+A)=(Tan2A+TanA)/1-Tan2A.TanA

={(2TanA/1-Tan^2A)+TanA}/{1-2TanA.TanA/(1-Tan^2A)}

=(2TanA+TanA-Tan^3A)/(1-3Tan^2A)

=(3TanA -Tan^3A)/(1-3Tan^2A)...Show more