Question

tan 35°/cot55° +cot78°/tan12°
?​

Answer 1

Answer:

$\frac{tan35}{cot55} + \frac{cot78}{tan12}$

$= \frac{tan35}{cot(90-35)} + \frac{cot(90-12)}{tan12}$

$= \frac{tan35}{tan35} + \frac{tan12}{tan12}$

$= 1+1$

$= 2$

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