tan^3theta+1/tantheta+1=sec^2theta-tantheta
Answers
Answered by
0
Answer:
Step-by-step explanation:
Tan³θ + 1 / Tanθ + 1
=> (Tanθ)³ + (1)³ / Tanθ + 1
//We know that a³ + b³ = (a+b)(a² - ab + b²)
=> (Tanθ + 1)(Tan²θ - Tanθ + 1) / Tanθ + 1
=> 1 + Tan²θ - Tanθ
=> Sec²θ - Tanθ (∵ 1 + Tan²θ = Sec²θ)
=> R.H.S
Hence Proved.
Similar questions