tan(π/4-Φ)=1-tanΦ/1-tanΦ
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Answer:
tan(π/4-x)=(1-tanx)/(1+tanx)
Step-by-step explanation:
tan(A-B)=(tanA-tanB)/(1+tanAtanB)
now substitute the value of A as π/4 and B as x
now we get
tan(π/4-x)=(1-tanx)/(1+tanx)
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