Question

Tan(π/4+A)tan(π/4-A)=1

Answer 1

your answer is here ✌✌✌✌✌✌✌

Answer 2

Hi ,

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We know that ,

Tan( A+B)= (tanA+tanB)/(1-tanAtanB)

Tan( π/4 + A ) = ( 1 + tanA)/(1 - tanA )
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Here ,

LHS = tan( π/4+A)tan(π/4-A)

= [(1+tanA)/(1-tanA)][(1-tanA)/(1+tanA)]

After cancellation ,we get

= 1

= RHS

I hope this helps you.

: )