Math, asked by Gtakya13579, 10 months ago

tan(45+B)=(cos2B)/(1-sin2B)

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Answered by anujdiwakr334

Answer:

sin2B = cos2A – sin2B = (1 – sin2A) – (1 – cos2B) = cos2B – sin2A (iii) tan (A + B + ... We have, (i) sin75° = sin (45° + 30°) = sin45° cos30° + cos45° sin30° [sin (A + B ...

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tan(45+B)=(cos2B)/(1-sin2B)​

Answers

tan(45+B)=(cos2B)/(1-sin2B)