tan 45 + sin45 upon
tan45 - sin 45
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Answer:
tan45 + sin45/ tan 45 - sin 45
=( 1+ 1/√2). / (1-1√2)
= √2+1 / √2-1
Answered by
3
★ Solution :-
tan45° + sin45°/tan45° - sin45°
As we know that,
• tan45° = 1
• sin45° = 1/√2
Substituting we have,
→ [ 1 + ( 1/√2 ) ]/[ 1 - ( 1/√2 ) ]
→ [ ( √2 + 1 )/√2 ]/[ ( √2 - 1 )/√2 ]
→ [ √2 + 1 ]/[ √2 - 1 ]
By Rationalizing the denominator,
→ [ √2 + 1/√2 - 1 ] × [ √2 + 1/√2 + 1 ]
Using ,
• ( a + b)(a + b) = ( a + b)² = a² + b² + 2ab
• (a + b)(a - b) = a² - b²
→ ( √2 + 1 )²/( √2 )² - (1)²
→ ( √2 )² + 1² + 2(√2)(1)/2 - 1
→ 2 + 1 + 2√2/1
→ 3 + 2√2
Hence , tan45° + sin45° ÷ tan45° - sin45° = 3 + 2√2.
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