tan (45+theta) please answer this question as soon as possible very urgent
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Hey friend....here is answer
![\tan(45 + \alpha ) = \frac{1 + \tan( \alpha) }{1 - \tan( \alpha ) } \tan(45 + \alpha ) = \frac{1 + \tan( \alpha) }{1 - \tan( \alpha ) }](https://tex.z-dn.net/?f=+%5Ctan%2845+%2B++%5Calpha+%29++%3D++%5Cfrac%7B1+%2B++%5Ctan%28+%5Calpha%29+%7D%7B1+-++%5Ctan%28+%5Calpha+%29+%7D+)
Hope it helps u
Hope it helps u
darshnideva23pb0txl:
please say with steps
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