Math, asked by SMAILY123, 11 months ago

tan(45°-A)=cosA-sinA/cosA+sinA

Answers

Answered by abhayraina1576

0

Step-by-step explanation:

Take LHS

Tan(45°-A)

= (Tan45° - TanA) / (1-Tan45°.TanA)

= 1-TanA / 1+TanA

= 1-SinA/CosA ÷ 1+SinA/CosA

= (CosA-SinA) / (CosA+SinA) = RHS

*Using Tan(A-B) = (TanA - TanB) ÷ (1+TanA.TanB)

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