Question

tan (45°-A) tan (45°+A)
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Answer 1

Answer:

tan(x+y ) = (tanx + tan y)/(1- tanx tany)

tan 45 = 1

lhs = tan(45+A)tan(45-A)

= (tan 45 +tan A)/(1- tan45tanA) * (tan45- tanA)/(1+tan45tanA)

= (1+tanA)/(1- tanA) * (1- tanA)/(1+tanA)

after cancellation  

=1

RHS

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Answer 2

Step-by-step explanation:

tan(x+y ) = (tanx + tan y)/(1- tanx tany)

tan 45 = 1

Ihs = tan(45+A)tan(45-A)

= (tan 45 +tan A)/(1- tan45tanA) * (tan45-

tanA)/(1+tan45tanA)

= (1+tanA)/(1- tanA) * (1- tanA)/(1+tanA)

after cancellation

=1

RHS

HOPE IT HELPS

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