tan(57+theta)*tan(33-theta)
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cot 90 minus 33 / tan 57+theta *cot 33- theta
so cot and tan cancelled and the ans is 1
hence proved
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Answered by
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Answer:
1
Step-by-step explanation:
tan( 57+theta) × tan( 33- theta,)
= tan (57+theta) × cot [ 90-(33-theta)]
= tan(57+theta) × 1/ tan ( 90-33+theta)
= tan (57+theta) / tan ( 57+theta)
= 1
Answer= 1
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