Question

tan 60° COS60° + cot 60° sin 60° is​

Answer 1

Answer:

Answer is

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Answer 2

$</p><p></p><p> \sf \rightarrow \quad tan \: 60^{\circ} \cdot cos \: 60^{\circ} + cot \: 60^{\circ} \cdot sin \: 60^{\circ} \\ \\</p><p></p><p> \sf \rightarrow \quad \dfrac{sin \: 60^{\circ} }{ \cancel{cos \: 60^{\circ} }} \cdot \cancel{cos \: 60^{\circ}} + \dfrac{ cos \: 60^{\circ} }{\cancel{ sin \: 60^{\circ}} } \cdot \cancel{sin \: 60^{\circ}} \\ \\ \sf \because \quad tan \: \theta = \dfrac{sin \: \theta}{cos \: \theta} \quad , \quad tan \: \theta = \dfrac{1}{cot \: \theta} </p><p></p><p>\\ \\ </p><p></p><p> \sf \rightarrow \quad sin \: 60^{\circ} + cos \: 60^{\circ} </p><p></p><p>\\ \\</p><p> \sf \rightarrow \quad 1 \\ \\ </p><p>\sf \quad sin \: \theta + cos \: \theta = 1 \\ \\</p><p></p><p>\sf Hence, \: Answer \: to \: this \: question \: is \: 1</p><p></p><p>$