Math, asked by mahimatripathi268, 6 months ago

tan 71°-cot19° का मान ज्ञात करो।

Answers

Answered by Enishkumarsahu

1

Answer:

$\tan71^0 - \cot19^ 0 \\tan90^0 -19^0-cot19^0 \\ \cot19^0 - \cot19 {}^{0} \\ = 0$

please mark me brainliest

Previous Question

Next Question

Similar questions

Math, 3 months ago

L+16=89 find value of L...

Math, 3 months ago

prove:(cosA-sinA)(1+tanA)/2cos2A-1 = secA...

Psychology, 3 months ago

Did you find remote classes more personal and interesting? How?- Answer this question, please. If you really answer it correctly, I will mark you as the brainliest and give a thank you and five stars.

Math, 6 months ago

*एक हरे पासे और एक नीले पासे को एक साथ फेका जाता है। इसकी क्या प्रायिकता है कि दोनों पासों से प्राप्त संख्याओं का योग 8 नहीं है?* 1️⃣ 5/36 2️⃣ 1/9 3️⃣ 8/9 4️⃣ 31/36...

Hindi, 6 months ago

शेवटचा शब्द शब्दसमूहाचा अर्थ लिहा...

English, 11 months ago

A. Rewrite the following in the indirect speech. 1. Mr Khanna said, "He doesn't know how to drive." 2. Mita said, "Ketan washed his bike yesterday." 3. You said, "We learnt the dialogues on time." Spark English Assignments - Class 5...

Math, 11 months ago

water is filled in a right cylindrical tank...

Social Sciences, 11 months ago

what is sericulture crop?