Math, asked by mahimatripathi268, 5 months ago

tan 71°-cot19° का मान ज्ञात करो।

Answers

Answered by Enishkumarsahu

1

Answer:

$\tan71^0 - \cot19^ 0 \\tan90^0 -19^0-cot19^0 \\ \cot19^0 - \cot19 {}^{0} \\ = 0$

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