tan (90 – A) •cot A cosec²A/cosec²A- cos²A = 0,Prove it.
Answers
Answered by
20
HELLO DEAR,
your questions is--------------> {tan(90 - A)*cotA/cosec²A} - cos²A
we know:- tan(90 - x) = cotx,
cosec²A = 1/sin²A, sec²A = 1/cos²A
Now, {tan(90 - A)*cotA/cosec²A} - cos²A
⇒{cotA*cotA/(1/sin²A)}- cos²A
⇒cot²A/(1/sin²A) - cos²A
⇒cos²A/sin²A * sin²A - cos²A
⇒cos²A - cos²A
⇒0
I HOPE ITS HELP YOU DEAR,
THANKS
Similar questions