Math, asked by AnkaniJogendra91, 1 year ago

sin 70/cos 20 + cosec 20/sec 70- 2cos 70 cosec20 = 0,Prove it.

Answers

Answered by anushka9217
66

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Answered by mysticd
78

Answer:

 \frac{sin70}{cos20}+\frac{cosec20}{sec70}-2cos70cosec20=0

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Step-by-step explanation:

LHS = \frac{sin70}{cos20}+\frac{cosec20}{sec70}-2cos70cosec20

=\frac{sin(90-20)}{cos20}+\frac{cosec(90-70)}{sec70}-2cos70cosec(90-70)

=\frac{cos20}{cos20}+\frac{sec70}{sec70}-2cos70sec70

=1+1-2cos70\times \frac{1}{cos70}

=1+1-2\\=2-2\\=0\\=RHS

Therefore,

 \frac{sin70}{cos20}+\frac{cosec20}{sec70}-2cos70cosec20=0

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