Question

sin48 sec42 + cos48 cosec42 = 2,Prove it.

Answer 1

sin48° sec42° + cos48° cosec42°




=> sin48° sec( 90 - 48 ) + cos48° cosec( 90 - 48 )


=> sin48° cosec48° + cos48° sec48°

$= > \sin(48) \frac{1}{ \sin(48) } + \cos(48) \frac{1}{ \cos(48) } \\ \\ = > 1 + 1 \\ \\ = > 2$



Proved.

Answer 2

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