Math, asked by rahulporika26, 1 year ago

Tan(90-A)cotA/cosec2-cos2=0

Answers

Answered by BrainlyUser007
10
tan(90°-A)cotA/cosec²A-cos²A
=cotA.cotA/cosec²A-cos²A [∵, tan(90°-A)=cotA]
=(cos²A/sin²A)/(1/sin²A)-cos²A
=cos²A-cos²A
=0 (Proved)
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