Question

tan(90+x)sin(180+x)sec(270+x)/cos(270-x)cosec(180-x)cot(360-x)=1

Answer 1

Step-by-step explanation:

Sin(180+x)=-sinx

cos(90+x)=-sinx

tan(270-x)=cotx

cot(360-x)=-cotx

sin(360-x)=-sinx

cos(360+x)=cosx

cosec(-x)=-cosecx

sin(270+x)=-cosx

therefore,

sin(180+x)cos(90+x)tan(270-x)cot(360-x)÷sin(360-x)cos(360+x)cosec(-x)sin(270+x)

=(-sinx)(-sinx)(cotx)(-cotx)÷(-sinx)(cosx)(-cosecx)(-cosx)

=(-sin x)(-sinx)(cosx/sinx)(-cosx)=1