Question

tan A = 3/4'tan B=4/3 | sin(A+B) = ?​

Answer 1

Answer:

Tan A + Tan B = Tan ( A + B ) × { 1 - Tan A × Tan B } Here Tan A = 3/4 And Tan B = 4/3 => (3/4) + (4/3) = Tan ( A + B ) { 1 - 1 }.