Tan(A+30)+cot(A-30)=1/(sin2A-sin60)...pls prove that...all angles in degrees?
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LHS = tan(A +
30) + cot(A - 30)
= (tanA + tan 30/1 – tanA.tan30 ) + (cotA.cot 30 + 1/cot30 - cotA)
Write this in terms of sine and cosine.
On solving with this we get the ans. As => 2 / 4cosA.sinA - √3
= (1 / 2sinA.cosA) - (√3/2)
= 1 / (sin2A - sin 60)
= RHS
= (tanA + tan 30/1 – tanA.tan30 ) + (cotA.cot 30 + 1/cot30 - cotA)
Write this in terms of sine and cosine.
On solving with this we get the ans. As => 2 / 4cosA.sinA - √3
= (1 / 2sinA.cosA) - (√3/2)
= 1 / (sin2A - sin 60)
= RHS
Anonymous:
pls tell if u didnt undrstnd...
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