tan(A-B)=1/√3 and tan(A+B)=√3/1
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tan ( A-B) = 1/√3
So A-B = π/6
tan(A+B)=√3/1
So A+B = π/3
2A = π/2
A= π/4
B=π/3 - π/4 = π/12
So A-B = π/6
tan(A+B)=√3/1
So A+B = π/3
2A = π/2
A= π/4
B=π/3 - π/4 = π/12
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