Tan a + b = 1 and Cos A - b =√3 ÷
2 find the value of a and b
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=> tan a + b = 1
:- tan a + b = tan 45
( tan 45 = 1 )
tan are common on both side
so,
a + b = 45 ........... ( i )
=> Cos a - b = √3/2
:- Cos a - b = Cos 30
( Cos 30 = √3/2 )
Cos are common both side
so,
a - b = 30 ...... ( ii )
Adding ( i ) and ( ii )
a + b + a - b = 45 + 30
2a = 75
a = 75/2
Putting value of a in equation ii
a - b = 30
(75/2) - b = 30
(75 - 2b)/2 = 30
75 - 2b = 30
-2b = 30-75
-2b = -45
b = 45/2
:- tan a + b = tan 45
( tan 45 = 1 )
tan are common on both side
so,
a + b = 45 ........... ( i )
=> Cos a - b = √3/2
:- Cos a - b = Cos 30
( Cos 30 = √3/2 )
Cos are common both side
so,
a - b = 30 ...... ( ii )
Adding ( i ) and ( ii )
a + b + a - b = 45 + 30
2a = 75
a = 75/2
Putting value of a in equation ii
a - b = 30
(75/2) - b = 30
(75 - 2b)/2 = 30
75 - 2b = 30
-2b = 30-75
-2b = -45
b = 45/2
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1
Answer:
the solution is in the attachment..
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