tan A+B=1 and tan A-B=1/√3 find A and B
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Answered by
2
Heya
_______________________________
Tan A + B = Tan 45
Becoz Tan 45 = 1
A + B = 45.... Equation ( i )
Tan ( A - B ) = Tan 30
Becoz Tan 30 = 1/√3
A - B = 30... Equation ( ii )
Adding both the equations
2A = 75
A = 37.5° And B = 7.5°
_______________________________
Tan A + B = Tan 45
Becoz Tan 45 = 1
A + B = 45.... Equation ( i )
Tan ( A - B ) = Tan 30
Becoz Tan 30 = 1/√3
A - B = 30... Equation ( ii )
Adding both the equations
2A = 75
A = 37.5° And B = 7.5°
Answered by
3
tan (A+B) = 1 = tan 45°
so, tan(A+B) = tan 45°
hence, A + B = 45. -------------------(i)
now, tan (A-B) = 1/ ✓3 = tan 30°
so, tan (A-B) = tan 30°
hence, A - B = 30. --------------------(ii)
(i) + (ii), we get
A + B + A - B = 45 + 30
2A = 75
A = (38.5)°
putting value of A in (ii)
38.5 - B = 30
B = (8.5)°
learnerpushp:
A = 37.5
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