Question

tan(a+b)=1,tan(a-b)=1/7.........then find tan a and tan b ....??? no spams ​

Answer 1

Answer:

Click here to get an answer to your question ✍️ If tan(A-B)=1/ROOT 3 and sin A =1/ root 2 then find the value of B.

Top answer · 37 votes

go through the solution step by step More

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Answer 2

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Explain:

tan (a + b) = 1 => tan (a - b) = 1/7

tan 2 a = tan (a+b + a -b) = [ tan(a+b) + tan (a-b) ]/[1 - tan (a+b) tan (a-b) ]

= (1 + 1/7) / (1 1/7) = 4/3 tan 2a = 2 tan a / (1- tan? a) = 4/3

=> 2 tana + 3 tan a - 2 = 0

=> tan a = [-3 + - V[ (9 + 16) ]/ 4 = -2 or 1/2

Now we have tan (a+b) = [tan a + tan b]/ [ 1 - tan a tan b ] => 1= [-2 + tan b]/[ 1+ 2 tan b]

If tan a = -2, then

> tan b = 3

if tan a = 1/2 then,

> 1=[ 1/2 + tan b]/[1 - 1/2 tan b] => tan b = 1/3

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