Question

Tan (A+B) =√3,cot(A-B)=√3 then find angle a and angle b​

Answer 1

Answer:

a=45°and b=15°

Step-by-step explanation:

tan (a+b) =√3

tan(a+b) = tan60°

a+b=60°......(1)

cot(a-b) = √3

cot(a-b) = cot30°

a-b =30°.......(2)

add equation (1) and (2) we get

a=45° and b=15°

Answer 2

Given

• Tan (A+B) =√3
• cot(A-B)=√3

To find

• angle a and angle b

Solution

we are provided with equations of tan and cot respectively and our asked to find the angles,

we know that tan 60 = √3

therefore, tan 60 = tan (A+B)

or, 60 = A+B

in a similar manner,

cot[A-B] = √3

or, 1/tan(A-B) = √3

or, tan(A-B) = 1/√3

= tan30

or, A-B = 30

solving both of the equations we get,

A= 45° and B = 15°

Therefore, the angle A is 45 degree and b is 15 degree