Question

tan(A+B)=√3 OR cos(A-B)=√3/2 ho to A or B ke maan hii

Answer 1

Answer:

$A=\frac{\pi}{4}$

$B=\frac{\pi}{12}$

Step-by-step explanation:

Given:

$tan(A+B)=\sqrt3$

$\implies\:A+B=\frac{\pi}{3}$.....(1)

and

$cos(A-B)=\frac{\sqrt3}{2}$

$\implies\:A-B=\frac{\pi}{6}$.....(2)

Now, we have

$A+B=\frac{\pi}{3}$.....(1)

$A-B=\frac{\pi}{6}$.....(2)

Adding (1) and (2)

$2A=\frac{\pi}{2}$

$A=\frac{\pi}{4}$

Subtracting (2) from (1)

$2B=\frac{\pi}{6}$

$B=\frac{\pi}{12}$