Question

Find the value of k for which the system of equations 2kx + 5y – 10 = 0 and 8x + 5ky – 8 = 0 has unique solution.

Answer 1

Answer:

Step-by-step explanation:

2kx+5y-10=0

8x+5ky-8=0

by unique soluion:

a1/a2≠b1/b2

here

a1=2k,b1=5,c1=-10

and

a2=8,b2=5k,c2=-8

so by formula:

a1/a2≠b1/b2

2k/8≠5/5k

k/4≠1/k

k²≠4

k≠2