Question

Find the value of k for which the system of equations 2kx + 5y – 10 = 0 and 8x + 5ky – 8 = 0 has unique solution.

Answer 1

Step-by-step explanation:

using matrix solution..

here,

changing equation in matrix form we get:

2k 5 x =10

8 5k y 8

for unique solution determinant must be zero.

so,

(2k*5k)-(8*5)=0

or, 10k^2 - 40=0

or, k^2=40/10

or, k^2=4

or,k=+-2

Hence value of k is 2..

Answer 2

Solution:

We have,

2kx+5y-10=0 — (I), and

8x+5ky-8=0 — (ii).

Now,

———uper ke answer se continue karo.