Math, asked by anudharmdubey, 1 year ago

tan A - cos A /sin A* cos A =sec^2 A -cosec^2 A

Answers

Answered by adeshrajputtirwa

0

Answer:

Step-by-step explanation:

=[(sinA/cosA)-cosA]/sinA.CosA

=[(sinA-cos^2A)/cosA]/sinA.cosA

=(sinA-cos^2A)/sinA.cos^2A

=SinA/sinA.cos^2A-cos^2A/sinA cos^2A

=sec^2A-cosecA

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