Question

(tan A+cot A)^2=sec^2 A + cosec^2 A​

Answer 1

Answer:

take LHS

(tanA+cotA)^2

=(sinA/cosA+cosA/sinA)^2

[: tanA=sinA/cosA

cotA=cosA/sinA]

sin^2A+cos^2A/(cosA. sinA) ^2

1/(cosA.sinA)^2

[:sin^2A+cos^2A=1]

(1/cos^2A) (1/sin^2A)

sec^2A+cosec^2A =RHS

[1/cosA=secA

1/sinA=cosecA]

LHS=RHS