(tan A + cot A) sin A X COSA = 1
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Answer:
Step-by-step explanation:
(TanA + CotA) SinA*CosA
=> (SinA/CosA + CosA/SinA) SinACosA
//Take LCM of the terms in brackets
=> (Sin²A + Cos²A/SinACosA) SinACosA
=> (1/SinACosA) SinACosA (∵ Sin²A + Cos²A = 1)
=> 1
Hence proved
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