Question

tan A + tan B + tanc
-sin( A+B+C)÷
cos Acos B cosc​

Answer 1

Answer:

tanA tanB tanC is the answer

Step-by-step explanation:

[(tanA + tanB + tanC ) - sin( A+B+C )] ÷ ( cosA cosB cosc)​

= tanA + tanB + tanC - [sin(A+B)*cosC + cos(A+B) *sinC]/cosA cosB cosC

= tanA + tanB + tan C -[sinA cosB cosC +cosAcosB cosC + cosAcosB sinC - sinA sinB sinC]/cosA cosB cosC

= tanA + tanB + tanC - tanA - tanB - tanC + tanA tanB tanC

= TanA tanB tanC

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