Question

tan alpha is equals to 8 by 15 find other trignometry ratio
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Answer 1

Step-by-step explanation:

$tan \alpha = \frac{8}{15}$

$tan \alpha = \frac{opposite \: side}{adjacent \: side}$

$from \: above \: triangle$

${8}^{2} + {15}^{2} = {x}^{2}$

$x = \sqrt{64 + 225}$

$x = \sqrt{289} = 17$

$\cos( \alpha ) = \frac{adjacent \: side}{hyp.} = \frac{15}{17}$

$\sin( \alpha ) = \frac{opposite \: side}{hyp.} = \frac{8}{17}$

$\cot( \alpha ) = \frac{1}{ \tan( \alpha ) } = \frac{1}{ \frac{8}{15} } = \frac{15}{8}$

$\ \sec ( \alpha ) = \frac{1}{ \cos( \alpha ) } = \frac{1}{ \frac{15}{17} } = \frac{17}{15}$

$\csc( \alpha ) = \frac{1}{ \sin( \alpha ) } = \frac{1}{ \frac{8}{17} } = \frac{17}{8}$