Question

tan inverse 2/3=1/2 tan inverse 12/5

Answer 1

Answer:

Step-by-step explanation:

$Consider\\\\2Tan^{-1}\frac{2}{3}\\\\=Tan^{-1}({\frac{\frac{2}{3}+\frac{2}{3}}{1-(\frac{2}{3})(\frac{2}{3})}})\\\\=Tan^{-1}\frac{12}{5}\\\\\\=>Tan^{-1}\frac{2}{3}=\frac{1}{2}Tan^{-1}\frac{12}{5}$

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