Question

tan inverse( sinx/1+cosx) =?... please I need this answer as soon as possible.

Answer 1

Answer:

Tan^-1 ( sin x / 1 + cos x)

= Tan^-1 ( 2 sin x/2 cos x/2 / 2 cos^2 x/2 )

= Tan^-1 ( sin x/2 / cos x/2 )

= Tan^-1 ( tan x/2 )

= X/2.

Answer 2

Answer:

Step-by-step explanation:

The given equation is:

$tan^{-1}(\frac{sinx}{1+cosx})$

Upon solving the above equation, we get

=$tan^{-1}(\frac{2sin\frac{x}{2}cos\frac{x}{2}}{2cos^2\frac{x}{2}})$

=$tan^{-1}(\frac{sin\frac{x}{2}}{cos\frac{x}{2}})$

=$tan^{-1}(tan\frac{x}{2})$

=$\frac{x}{2}$

Which is the required simplified form.