tan inverse x + tan inverse 2x = π\2
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Heya!
Tan-¹ A + Tan-¹ B =
Tan-¹ { (A + B )/(1-A×B)}
=>
Tan-¹ x + Tan-¹ 2x = π/2
Tan-¹ { ( 3x )/(1-2x² ) } = π/2
3x / ( 1-2x² ) = Tan π/2
3x / ( 1 -2x² ) = 1/0
Becoz Tan 90 = 1/0
( 1 - 2x² ) = 0
x = ±1/√2
ajaykumar3113:
very nice
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