tan (pi/4 + x) = 1 + tan x/1 - tanx
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Hi !
We know that tan ( A + B) = tanA + tanB / 1 - tanA * tanB
Since,
tan ( π/4 + x ) = tanπ/4 + tanx / 1 - tanπ/4*tanx
1 + tanx / 1 - tanx. .. [°•°tanπ/4 = 1 ]
Since , prooved ♻
LHS = RHS
_____________________________
Hope it helps you !!;
@Rajukumar111
We know that tan ( A + B) = tanA + tanB / 1 - tanA * tanB
Since,
tan ( π/4 + x ) = tanπ/4 + tanx / 1 - tanπ/4*tanx
1 + tanx / 1 - tanx. .. [°•°tanπ/4 = 1 ]
Since , prooved ♻
LHS = RHS
_____________________________
Hope it helps you !!;
@Rajukumar111
tushi88:
Hiio
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