Question

tan' (sec 30+tan 30) de​

Answer 1

Step-by-step explanation:

not appropriate question

Answer 2

tan ( sec 30° + tan 30° )

= tan ( 2 / √3 + 1 / √3 )

= tan ( 2+1 / √3 )

= tan ( 3 / √3 )

= tan ( 3 / √3 * √3 / √3 )

= tan ( 3 * √3 / √3 * √3 )

= tan ( 3√3 / 3 )

= tan ( √3 )

but tan 60° = √3

:. theta = 60°