Question

tan square 60 + cot square 30/ sin square 30 + cos square 60​

Answer 1

your answer is 12

plz mark as brainliest

Answer 2

$\dfrac{\tan^2 60+\cot^2 30}{\sin^2 30+\cos^2 60}=12$

Step-by-step explanation:

Given : Expression $\dfrac{\tan^2 60+\cot^2 30}{\sin^2 30+\cos^2 60}$

To find : The value of the expression ?

Solution :

Using trigonometric values,

$\sin 30^\circ=\frac{1}{2}$

$\cos 60^\circ=\frac{1}{2}$

$\tan 60^\circ=\sqrt3$

$\cot 30^\circ=\sqrt3$

Expression $\dfrac{\tan^2 60+\cot^2 30}{\sin^2 30+\cos^2 60}$

Substitute the values in the expression,

$=\dfrac{(\sqrt3)^2+(\sqrt3)^2}{(\frac{1}{2})^2+(\frac{1}{2})^2}$

$=\dfrac{3+3}{\frac{1}{4}+\frac{1}{4}}$

$=\dfrac{6}{\frac{2}{4}}$

$=\dfrac{6\times 4}{2}$

$=12$

Therefore, $\dfrac{\tan^2 60+\cot^2 30}{\sin^2 30+\cos^2 60}=12$

#Learn more

Evaluate:tan square 30°.sin 30°+cos 60°.sin square 90°.tan square 60°-2.tan 45°.cos square 0°.sin square 90°

https://brainly.in/question/7024656