Question

tan square A + cot square A =sec square A cosec square A -2​

Answer 1

Answer:

L.H.S.

$\tan^{2} (a) + \cot^{2} (a) \\ = \sec ^{2} (a) - 1 + \cosec^{2} (a) - 1 \\ = (1 \div \cos(a) + 1 \div \sin(a)) ^{2} - 2 \\ = ( \sin(a) + \cos(a) \div \sin(a) \cos(a) )^{2} - 2 \\ = \sin^{2} (a) + cos^{2}(a) \div \sin^{2} (a) \cos ^{2} (a) - 2 \\ = 1 \div \sin^{2} (a) \cos ^{2} (a) - 2 \\ = \sec^{2} (a) \cosec^{2} (a) - 2 \\ hence \: proved$

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Answer 2

Answer:

hope its help you

sin^2+cos^2=1

this identity is used here.