A tower is broken at a height of 12 m from the floor and its top touches the floor at a distance of 5 metres from the base of the tower find the actual height of the tower
Answers
If the broken part of the tower touches the ground 5 m away from the foot the tower then the actual height of the tower is 25 m.
Explanation:
Referring to the figure attached below, let's make some assumptions
The height from the floor up to the broken portion of tower, AB = 12 m
The distance from between the foot of the tower and the tip of the tower touching the floor, BC = 5 m
Let the height of the broken part of the tower be AC = "x" meter
Since the tower stands vertical with the floor therefore we can consider the Δ ABC as right angled triangle.
Applying the Pythagoras Theorem in ΔABC, we get
AC² = AB² + BC²
⇒ x² = [12² + 5²]
⇒ x² = 144 + 25
⇒ x = √169
⇒ x = 13 m
Thus,
The actual height of the tower is given as,
= 12 + x
= 12 + 13
= 25 m
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